%@Auteur:Véronique Glaçon\par Après avoir découpé les dominos ci-dessous, place les pour former un parcours rectangulaire en respectant la règle suivante : {\em deux côtés qui sont adjacents doivent être égaux}. \hspace{0.5cm} \renewcommand\arraystretch{2.5} \begin{table}[h!] \begin{minipage}[t]{.5\linewidth} \begin{tabular}{|p{3.5cm}||p{3.5cm}|} \hline \centering{$2(x+7)$ \\ \hspace{1cm}} & \centering{$4x+3-7x+9$ \\ \hspace{1cm}} \tabularnewline \hline \end{tabular} \end{minipage} \hfill \begin{minipage}[t]{.5\linewidth} \begin{tabular}{|p{3.5cm}||p{3.5cm}|} \hline \centering{$2x(4-3x)$ \\ \hspace{1cm}} & \centering{$3(x-1)$ \\ \hspace{1cm}} \tabularnewline \hline \end{tabular} \end{minipage}\end{table} \begin{minipage}[t]{.5\linewidth} \begin{tabular}{|p{3.5cm}||p{3.5cm}|} \hline \centering{$3-2x+4+4x$ \\ \hspace{1cm}} & \centering{$2x+14$ \\ \hspace{1cm}} \tabularnewline \hline \end{tabular} \end{minipage} \hfill \begin{minipage}[t]{.5\linewidth} \begin{tabular}{|p{3.5cm}||p{3.5cm}|} \hline \centering{$x^2-3$} & \centering{$2x+3$ \\ \hspace{1cm}} \tabularnewline \hline \end{tabular} \end{minipage} \begin{table}[h!] \begin{minipage}[t]{.5\linewidth} \begin{tabular}{|p{3.5cm}||p{3.5cm}|c} \hline \centering{ $9-4x-9+7x$\\ \hspace{1cm}} & \centering{$37-13x$ \\ \hspace{1cm}} \tabularnewline \hline \end{tabular} \end{minipage} \hfill \begin{minipage}[t]{.5\linewidth} \begin{tabular}{|p{3.5cm}||p{3.5cm}|} \hline \centering{$-3x+12$ \\ \hspace{1cm}} & \centering{$x(x-3)$ \\ \hspace{1cm}} \tabularnewline \hline \end{tabular} \end{minipage}\end{table} \begin{minipage}[t]{.5\linewidth} \begin{tabular}{|p{3.5cm}||p{3.5cm}|} \hline \centering{$5$ \\ \hspace{1cm}} & \centering{$2x+7$ \\ \hspace{1cm}} \tabularnewline \hline \end{tabular} \end{minipage} \hfill \begin{minipage}[t]{.5\linewidth} \begin{tabular}{|p{3.5cm}||p{3.5cm}|} \hline \centering{$2(x-4)+5(9-3x)$ \\ \hspace{1cm}} & \centering{$-6x^2+8x$ \\ \hspace{1cm}} \tabularnewline \hline \end{tabular} \end{minipage} \begin{table}[h!] \begin{minipage}[t]{.5\linewidth} \begin{tabular}{|p{3.5cm}||p{3.5cm}|} \hline \centering{$-1+2(2+x)$ \\ \hspace{1cm}} & \centering{$3x-3$ \\ \hspace{1cm}} \tabularnewline \hline \end{tabular} \end{minipage} \hfill \begin{minipage}[t]{.5\linewidth} \begin{tabular}{|p{3.5cm}||p{3.5cm}|} \hline \centering{$4(x-3)-4x+17$} & \centering{$3x$ \\ \hspace{1cm}} \tabularnewline \hline \end{tabular} \end{minipage} \end{table} \renewcommand\arraystretch{1}