additionfractions.tex

\documentclass[11pt]{article}
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\parindent1pt
\topmargin0pt\headsep0pt\headheight0pt\footskip0pt
\usepackage[a4paper,margin=5mm]{geometry}
\usepackage{amsmath,tabularx}
\usepackage{color}
\usepackage{textcomp,enumerate}
\usepackage{fancybox}
\usepackage{shadow}
\usepackage{graphicx}
\usepackage{ifthen}
\usepackage{ulem}
\usepackage{soul}
\usepackage{multicol}
\usepackage{picins}
 
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\newboolean{visible}
 
\newcommand{\blanc}[1]{%
\textcolor{red}{\ifthenelse{\boolean{visible}}{#1}{\uwave{\phantom{#1}}}}%
}
\newcommand{\blancns}[1]{%
\textcolor{red}{\ifthenelse{\boolean{visible}}{#1}{ \phantom{\large #1}}}%
}
\newcommand{\barem}[1]{%
\textcolor{green}{\ifthenelse{\boolean{visible}}{\textsf{#1}}{}}%
}
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%------------------------------------------------
%redefinition des listes numérotées (copie de chris5.tex)
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\def\labelenumi{{\bf \theenumi °)}}
 
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\newcounter{numeroexo}
\newcommand{\exo}{\par\noindent\stepcounter{numeroexo}
	\hspace{-.25cm}\Ovalbox{\textbf{Exercice \arabic{numeroexo}}}\;}
 
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\newcommand{\pts}[2]{\noindent
	\textcolor{red}{\textsl{(sur #1 points)}}\; %#1 pour le nombre de points
	\textcolor{blue}{\textsc{#2 }}}	%#2 pour le titre de l'exo
 
\pagestyle{empty}
\definecolor{grisclair}{gray}{0.96}
 
\begin{document}
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\setboolean{visible}{false}		%Cacher la correction en mettant "false" pour la variable "visible" 
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\begin{center}
\ifthenelse{\boolean{visible}}{
\fcolorbox{red}{grisclair}{{\bf \strut \qquad Correction Addition de fractions \qquad \strut}}\par}
{\fcolorbox{blue}{grisclair}{{\bf \strut \qquad Addition de fractions \qquad \strut}}\par}
\end{center}
%°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
\ifthenelse{\boolean{visible}}{}{\vspace*{-.2cm}}
\uuline{\textbf{Ecris la fraction qui représente la partie coloriée de chaque figure :}}
\ifthenelse{\boolean{visible}}{}{\vspace*{-.2cm}}
\begin{multicols}{8}
\includegraphics{additfractions.1} $$\dfrac{\blanc{7}}{\blanc{14}}\,ou\, \dfrac{\blanc{1}}{\blanc{2}}$$
\includegraphics{additfractions.2} $$\dfrac{\blanc{1}}{\blanc{3}}$$
\includegraphics{additfractions.3} $$\dfrac{\blanc{6}}{\blanc{9}}\,ou\, \dfrac{\blanc{2}}{\blanc{3}}$$
\includegraphics{additfractions.4} $$\dfrac{\blanc{4}}{\blanc{9}}$$
\includegraphics{additfractions.9} $$\dfrac{\blanc{8}}{\blanc{32}}\,ou\, \dfrac{\blanc{1}}{\blanc{4}}$$
\includegraphics{additfractions.6} $$\dfrac{\blanc{2}}{\blanc{8}}\,ou\, \dfrac{\blanc{1}}{\blanc{4}}$$
\includegraphics{additfractions.7} $$\dfrac{\blanc{4}}{\blanc{8}}\,ou\, \dfrac{\blanc{1}}{\blanc{2}}$$
\includegraphics{additfractions.8} $$\dfrac{\blanc{2}}{\blanc{4}}\,ou\, \dfrac{\blanc{1}}{\blanc{2}}$$
\end{multicols}
\ifthenelse{\boolean{visible}}{}{\vspace*{-.3cm}}
\textbf{Complète la règle :} 
\ifthenelse{\boolean{visible}}{}{\vspace*{-.2cm}}
\begin{center}
\shabox{\textit {La fraction coloriée d'une figure = $\dfrac{nombre\, de\, parties\, \blanc{colori\acute{e}es}}{nombre\, de\, parties\, \blanc{totales}}$\; si toutes les parties sont \blanc{égales.}}}
\end{center}
\uuline{\textbf{Effectue le coloriage correspondant aux fractions pour pouvoir trouver le résultat des opérations :}}
\begin{multicols}{2}
\begin{tabular}{>\centering m{2.5cm}@{+}>\centering m{2.5cm}@{= }m{2.5cm}}
\ifthenelse{\boolean{visible}}{\includegraphics{additfractions.11}}{\includegraphics{additfractions.10}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.12}}{\includegraphics{additfractions.10}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.13}}{\includegraphics{additfractions.10}} \\
$\dfrac{2}{4}$ & $\dfrac{1}{4}$ & $\dfrac{\blanc{2}+\blanc{1}}{\blanc{4}}=\dfrac{\blanc{3}}{\blanc{4}}$
\end{tabular}
 
\begin{tabular}{>\centering m{2.5cm}@{+}>\centering m{2.5cm}@{= }m{2.5cm}}
\ifthenelse{\boolean{visible}}{\includegraphics{additfractions.15}}{\includegraphics{additfractions.14}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.16}}{\includegraphics{additfractions.14}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.17}}{\includegraphics{additfractions.14}} \\
$\dfrac{5}{16}$ & $\dfrac{7}{16}$ & $\dfrac{\blanc{5}+\blanc{7}}{\blanc{16}}=\dfrac{\blanc{12}}{\blanc{16}}$
\end{tabular}
\vspace{.3cm}
\begin{tabular}{>\centering m{2.5cm}@{+}>\centering m{2.5cm}@{= }m{2.5cm}}
\ifthenelse{\boolean{visible}}{\includegraphics{additfractions.19}}{\includegraphics{additfractions.18}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.20}}{\includegraphics{additfractions.18}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.21}}{\includegraphics{additfractions.18}} \\
$\dfrac{1}{8}$ & $\dfrac{4}{8}$ & $\dfrac{\blanc{1}+\blanc{4}}{\blanc{8}}=\dfrac{\blanc{5}}{\blanc{8}}$
\end{tabular}
 
\begin{tabular}{>\centering m{2.5cm}@{+}>\centering m{2.5cm}@{= }m{2.5cm}}
\ifthenelse{\boolean{visible}}{\includegraphics{additfractions.24}}{\includegraphics{additfractions.22}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.23}}{\includegraphics{additfractions.22}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.25}}{\includegraphics{additfractions.22}} \\
$\dfrac{1}{5}$ & $\dfrac{2}{5}$ & $\dfrac{\blanc{1}+\blanc{2}}{\blanc{5}}=\dfrac{\blanc{3}}{\blanc{5}}$
\end{tabular}
\end{multicols}
\ifthenelse{\boolean{visible}}{}{\vspace*{-.2cm}}
\textbf{Complète la règle :} 
\ifthenelse{\boolean{visible}}{}{\vspace*{-.2cm}}
\begin{center}
\shabox{\textit {Quand les dénominateurs sont \blanc{égaux}, on peut ajouter les \blanc{numérateurs}. On ne change pas les \blanc{dénominateurs}.}
}
\end{center}
 
\begin{multicols}{2}
\begin{tabular}{>\centering m{2.5cm}@{+}>\centering m{2.5cm}@{= }m{2.5cm}}
\ifthenelse{\boolean{visible}}{\includegraphics{additfractions.11}}{\includegraphics{additfractions.10}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.12}}{\includegraphics{additfractions.10}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.13}}{\includegraphics{additfractions.10}} \\
$\dfrac{1}{2}$ & $\dfrac{1}{4}$ & $\dfrac{\blanc{2}}{\blanc{4}}+\dfrac{1}{4}=\dfrac{\blanc{3}}{\blanc{4}}$
\end{tabular}
 
\begin{tabular}{>\centering m{2.5cm}@{+}>\centering m{2.5cm}@{= }m{2.5cm}}
\ifthenelse{\boolean{visible}}{\includegraphics{additfractions.27}}{\includegraphics{additfractions.26}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.28}}{\includegraphics{additfractions.26}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.29}}{\includegraphics{additfractions.26}} \\
$\dfrac{1}{4}$ & $\dfrac{7}{20}$ & $\dfrac{\blanc{5}}{\blanc{20}}+\dfrac{7}{20}=\dfrac{\blanc{12}}{\blanc{20}}$
\end{tabular}
\vspace{.4cm}
\begin{tabular}{>\centering m{2.5cm}@{+}>\centering m{2.5cm}@{= }m{2.5cm}}
\ifthenelse{\boolean{visible}}{\includegraphics{additfractions.19}}{\includegraphics{additfractions.18}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.20}}{\includegraphics{additfractions.18}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.21}}{\includegraphics{additfractions.18}} \\
$\dfrac{1}{8}$ & $\dfrac{1}{2}$ & $\dfrac{1}{8}+\dfrac{\blanc{4}}{\blanc{8}}=\dfrac{\blanc{5}}{\blanc{8}}$
\end{tabular}
 
\begin{tabular}{>\centering m{2.5cm}@{+}>\centering m{2.5cm}@{= }m{2.5cm}}
\ifthenelse{\boolean{visible}}{\includegraphics{additfractions.31}}{\includegraphics{additfractions.30}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.32}}{\includegraphics{additfractions.30}} & \ifthenelse{\boolean{visible}}{\includegraphics{additfractions.33}}{\includegraphics{additfractions.30}} \\
$\dfrac{1}{3}$ & $\dfrac{2}{9}$ & $\dfrac{\blanc{3}}{\blanc{9}}+\dfrac{2}{9}=\dfrac{\blanc{5}}{\blanc{9}}$
\end{tabular}
\end{multicols}
\ifthenelse{\boolean{visible}}{}{\vspace*{-.2cm}}
\textbf{Complète la règle :} 
\ifthenelse{\boolean{visible}}{}{\vspace*{-.2cm}}
\begin{center}
\shabox{\parbox{17cm}{\textit {Quand les dénominateurs sont \blanc{différents}, on ne  peut pas  ajouter les \blanc{numérateurs}. On doit transformer les \blanc{dénominateurs}  pour  les  rendre  \blanc{égaux}, ensuite on peut \blanc{ajouter} les nouveaux numérateurs.}}}
\end{center}
\textbf{Calculer :} \\[.2cm]
\begin{tabular}{p{6.5cm}|p{6.5cm}|p{6.5cm}}
$\dfrac{1}{7}+\dfrac{3}{14}=\dfrac{\blanc{2}}{14}+\dfrac{3}{14}=\dfrac{\blanc{2}+\blanc{3}}{14}=\dfrac{\blanc{5}}{14}$ &
$\dfrac{2}{5}+\dfrac{7}{30}=\dfrac{\blanc{12}}{\blanc{30}}+\dfrac{7}{30}=\dfrac{\blanc{12}+\blanc{7}}{30}=\dfrac{\blanc{19}}{30}$&
$\dfrac{3}{8}+\dfrac{5}{64}=\dfrac{\blanc{16}}{\blanc{64}}+\dfrac{\blanc{5}}{\blanc{64}}=\dfrac{\blanc{16+5}}{\blanc{64}}=\dfrac{\blanc{21}}{\blanc{64}}$
\end{tabular}
 
\end{document}