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\documentclass[a4paper,11pt]{article}
\usepackage{francois_meria}
\usepackage[dvips]{graphicx}
\usepackage[dvips]{epsfig}
\setlength{\parindent}{0mm}
    \lhead{\textsf{Collège Château Forbin} - \textit{Mathématiques} - \textsf{6\ieme}}
    \chead{}
    \rhead{\textit{Année} 2005/2006}
    \pagestyle{fancy}
  \renewcommand{\headrulewidth}{0.5pt}
 
 
\makeatletter
% use transpalpha=<mumber> to the the opacity level
\define@key[psset]{}{transpalpha}{\pst@checknum{#1}\pstranspalpha}
\psset{transpalpha=1}
\def\psfs@transp{%
  \addto@pscode{/Normal .setblendmode \pstranspalpha .setshapealpha }
  \psfs@solid}
\makeatother
 
\begin{document}
 
\begin{center}
\begin{tabularx}{\textwidth}{|X|}
\hline
 
\vskip 0.1cm
\begin{center}
    {\Large\textbf{Construction géométrique : Triangles et cercles !}}\\
 
    \vskip 0.025cm
 
\end{center}\\
\hline
\end{tabularx}
\end{center}
 
\vskip 0.55cm
 
Il s'agit de construire la figure 2 ci-dessous.
 
\begin{multicols}{2}
\begin{center}
\psset{unit=0.46cm}
    \pspicture(-4,-2.2)(17.5,14.5)
        \pstGeonode[PointSymbol=none,PosAngle={-135,-45}](0,0){B}(12,0){C}              \pstRotation[PointSymbol=none,RotAngle=60,PosAngle=90]{B}{C}{A}
        \pstMiddleAB[PointSymbol=none,PosAngle=-90]{B}{C}{J}
        \pstMiddleAB[PointSymbol=none,PosAngle=45]{A}{C}{K}
        \pstMiddleAB[PointSymbol=none,PosAngle=135]{B}{A}{I}
        \pstInterLL[PointSymbol=none,PointName=none]{A}{J}{B}{K}{O}
        \pstInterLC[Radius=\pstDistVal{2},PointSymbol=x,PointSymbolA=none,PosAngle=-90,PointNameA=none]{A}{O}{J}{}{Z_3}{D}
        \pstInterLC[Radius=\pstDistVal{2},PointSymbol=x,PointSymbolA=none,PosAngle=135,PointNameA=none]{C}{O}{I}{}{Z_1}{E}
        \pstInterLC[Radius=\pstDistVal{2},PointSymbol=x,PointSymbolA=none,PosAngle=45,PointNameA=none]{B}{O}{K}{}{Z_2}{F}
        \pstTranslation[PointSymbol=none,PointName=none]{I}{E}{A}{t}
        \pstTranslation[PointSymbol=none,PointName=none]{K}{F}{A}{p}
        \pstTranslation[PointSymbol=none,PointName=none]{J}{D}{B}{q}
        \pstInterLL[PointSymbol=none,PosAngle=-135]{D}{q}{E}{t}{B'}
        \pstInterLL[PointSymbol=none,PosAngle=-45]{D}{q}{p}{F}{C'}
        \pstInterLL[PointSymbol=none,PosAngle=90]{F}{p}{E}{t}{A'}
        \pspolygon(A')(B')(C')
        \pstArcOAB[linewidth=1pt]{I}{B}{A}
        \pstArcOAB[linewidth=1pt]{E}{B}{A}
        \pstArcOAB[linewidth=1pt]{K}{A}{C}
        \pstArcOAB[linewidth=1pt]{F}{A}{C}
        \pstArcOAB[linewidth=1pt]{J}{C}{B}
        \pstArcOAB[linewidth=1pt]{D}{C}{B}
        \pstLineAB[linestyle=dashed]{C}{E}
        \pstLineAB[linestyle=dashed]{B}{F}
        \pstLineAB[linestyle=dashed]{A}{D}
        \pspolygon[linestyle=dashed](A)(B)(C)
        \put(5,-3.8){Figure $1$}
        \pstRightAngle{C}{E}{B'}
        \pstRightAngle{B}{F}{C'}
        \pstRightAngle{A}{D}{C'}
    \endpspicture
\end{center}
 
\columnbreak
 
\begin{center}
\psset{unit=0.46cm}
    \pspicture(-4,-2.2)(16,14.5)
        \pstGeonode[PointSymbol=none,PosAngle={-135,-45},PointName=none](0,0){B}(12,0){C}
        \pstRotation[PointSymbol=none,RotAngle=60,PosAngle=90,PointName=none]{B}{C}{A}
        \pstMiddleAB[PointSymbol=none,PosAngle=-45,PointName=none]{B}{C}{J}
        \pstMiddleAB[PointSymbol=none,PosAngle=45,PointName=none]{A}{C}{K}
        \pstMiddleAB[PointSymbol=none,PosAngle=135,PointName=none]{B}{A}{I}
        \pstInterLL[PointName=none,PointSymbol=none]{A}{J}{B}{K}{O}
        \pstInterLC[Radius=\pstDistVal{2},PointName=none,PointSymbol=none,PosAngle=-90]{A}{O}{J}{}{Z_3}{D}
        \pstInterLC[Radius=\pstDistVal{2},PointName=none,PointSymbol=none,PosAngle=135]{C}{O}{I}{}{Z_1}{E}
        \pstInterLC[Radius=\pstDistVal{2},PointName=none,PointSymbol=none,PosAngle=45]{B}{O}{K}{}{Z_2}{F}
        \pstTranslation[PointName=none,PointSymbol=none]{I}{E}{A}{t}
        \pstTranslation[PointName=none,PointSymbol=none]{K}{F}{A}{p}
        \pstTranslation[PointName=none,PointSymbol=none]{J}{D}{B}{q}
        \pstInterLL[PointName=none,PointSymbol=none]{D}{q}{E}{t}{B'}
        \pstInterLL[PointName=none,PointSymbol=none]{D}{q}{p}{F}{C'}
        \pstInterLL[PointName=none,PointSymbol=none]{F}{p}{E}{t}{A'}
        \pspolygon[linewidth=1.5pt](A')(B')(C')
        \pstArcOAB[linewidth=1.5pt]{I}{B}{A}
        \pstArcOAB[linewidth=1.5pt]{E}{B}{A}
        \pstArcOAB[linewidth=1.5pt]{K}{A}{C}
        \pstArcOAB[linewidth=1.5pt]{F}{A}{C}
        \pstArcOAB[linewidth=1.5pt]{J}{C}{B}
        \pstArcOAB[linewidth=1.5pt]{D}{C}{B}
        \put(5,-3.8){Figure $2$}
    \endpspicture
\end{center}
\end{multicols}
\vskip 1.5cm
 
\textbf{\LARGE Programme de construction }\\
 
\large{\texttt{Toutes les constructions doivent se faire à
l'équerre, à la règle et au compas.}}\\
 
\vskip 0.5cm
 
\shadowbox{
\begin{minipage}[c]{\textwidth}
\begin{multicols}{2}\setlength{\columnseprule}{0.5pt}
\textbf{\'Etape 1.}\\
Tracer un triangle équilatéral $ABC$ de côté 12~cm et repérer les milieux $I$, $J$ et $K$ de chaque côté.\\
 
\textbf{\'Etape 2.}\\
Tracer les cercles de diamètres les côtés du triangle $ABC$.\\
 
\textbf{\'Etape 3.}\\
Tracer les segments joingant chaque sommet du triangle au milieu du côté opposé. On parle de médianes du triangle.\\
Prolonger ces médianes de 2~cm ; on obtient les points $D$, $E$ et
$F$.\\
\textbf{\'Etape 4.}\\
Tracer les perpendiculaires à ces médianes passant par les
points $D$, $E$ et $F$. On obtient un nouveau triangle $A'B'C'$.\\
 
\textbf{\'Etape 5.}\\
Tracer des arcs de cercles ayant pour centre $D$, $E$ et $F$ et passant respectivement par $B$ et $C$,
$A$ et $B$ et $A$ et $C$.\\
 
\textbf{\'Etape 6.}\\
Colorier la figure en alternant deux couleurs.\\
\end{multicols}
\end{minipage}
}
\end{document}