Source
%@metapost:4calcullitteral404exo024.mp
%@Dif:2
Développe les expressions suivantes et indique les différents termes de la réponse sur le dessin. ({\em Les quadrilatères qui interviennent sont soit des carrés soit des rectangles}.)
\begin{center}
\begin{multicols}{3}
\includegraphics{4calcullitteral404exo024.1}\par\vspace{5mm}\par
\Eqalign{ \rnode{A}{c}\times(\rnode{B}{a}+\rnode{C}{b})&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }
\ncarc[arcangle=60,offset=1mm]{->}{A}{B}
\ncarc[arcangle=60,offset=1mm]{->}{A}{C}
\par
\includegraphics{4calcullitteral404exo024.2}\par\vspace{5mm}
\Eqalign{ \rnode{A}{c}\times(\rnode{B}{c}+\rnode{C}{b})&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }
\ncarc[arcangle=60,offset=1mm]{->}{A}{B}
\ncarc[arcangle=60,offset=1mm]{->}{A}{C}
\par
\includegraphics{4calcullitteral404exo024.3}\par\vspace{5mm}
\Eqalign{ \rnode{A}{2b}\times(\rnode{B}{3b}+\rnode{C}{a})&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }
\ncarc[arcangle=45,offset=1mm]{->}{A}{B}
\ncarc[arcangle=45,offset=1mm]{->}{A}{C}
\end{multicols}
\par
\begin{multicols}{3}
\includegraphics{4calcullitteral404exo024.4}\par\vspace{5mm}\par
\Eqalign{ a\times(2a+5c)&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }
\par
\includegraphics{4calcullitteral404exo024.5}\par\vspace{5mm}\par
\Eqalign{ 3a\times(4a+b)&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }
\par
\includegraphics{4calcullitteral404exo024.6}\par\vspace{5mm}\par
\Eqalign{ (a+2c)\times5c&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }
\end{multicols}
\end{center}