%@metapost:4calcullitteral404exo024.mp %@Dif:2 Développe les expressions suivantes et indique les différents termes de la réponse sur le dessin. ({\em Les quadrilatères qui interviennent sont soit des carrés soit des rectangles}.) \begin{center} \begin{multicols}{3} \includegraphics{4calcullitteral404exo024.1}\par\vspace{5mm}\par $\Eqalign{ \rnode{A}{c}\times(\rnode{B}{a}+\rnode{C}{b})&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }$ \ncarc[arcangle=60,offset=1mm]{->}{A}{B} \ncarc[arcangle=60,offset=1mm]{->}{A}{C} \par \includegraphics{4calcullitteral404exo024.2}\par\vspace{5mm} $\Eqalign{ \rnode{A}{c}\times(\rnode{B}{c}+\rnode{C}{b})&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }$ \ncarc[arcangle=60,offset=1mm]{->}{A}{B} \ncarc[arcangle=60,offset=1mm]{->}{A}{C} \par \includegraphics{4calcullitteral404exo024.3}\par\vspace{5mm} $\Eqalign{ \rnode{A}{2b}\times(\rnode{B}{3b}+\rnode{C}{a})&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }$ \ncarc[arcangle=45,offset=1mm]{->}{A}{B} \ncarc[arcangle=45,offset=1mm]{->}{A}{C} \end{multicols} \par \begin{multicols}{3} \includegraphics{4calcullitteral404exo024.4}\par\vspace{5mm}\par $\Eqalign{ a\times(2a+5c)&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }$ \par \includegraphics{4calcullitteral404exo024.5}\par\vspace{5mm}\par $\Eqalign{ 3a\times(4a+b)&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }$ \par \includegraphics{4calcullitteral404exo024.6}\par\vspace{5mm}\par $\Eqalign{ (a+2c)\times5c&=\hbox to2.5cm{\dotfill}\cr &=\hbox to2.5cm{\dotfill}\cr }$ \end{multicols} \end{center}