%@P:exocorcp %@Auteur: François Meria \begin{multicols}{2} \begin{center} \begin{pspicture}(0,0.1)(8,1.3) \psline(0,.5)(8,.5) \psdots[dotstyle=+,dotangle=45,dotsize=0.2](1.2,0.5)\uput[90](1.2,0.5){$A$} \psdots[dotstyle=+,dotangle=45,dotsize=0.2](2.2,0.5)\uput[90](2.2,0.5){$B$} \psdots[dotstyle=+,dotangle=45,dotsize=0.2](5,1)\uput[90](5,1){$C$} \psdots[dotstyle=+,dotangle=45,dotsize=0.2](6,0.5)\uput[90](6,0.5){$D$} \psdots[dotstyle=+,dotangle=45,dotsize=0.2](4,0.5)\uput[90](4,0.5){$E$} \end{pspicture} \end{center} \par \columnbreak \par \noindent Compléter en utilisant les symboles d'appartenance $\in$ et de non-appartenance $\notin$.\\ \begin{center} \begin{tabular}{cccccc} $B \ \dots\ [AE]$ & \qquad \qquad & $B \ \dots\ [AD]$ & \qquad \qquad & $C \ \dots\ [ED]$ \\ $C \ \dots\ [AB)$ & \qquad \qquad & $E \ \dots\ [AD)$ & \qquad \qquad & $E \ \dots\ [AB)$ \\ $B \ \dots\ [ED)$ & \qquad \qquad & $B \ \dots\ (ED)$ & \qquad \qquad & $B \ \dots\ [AB]$ \\ \end{tabular} \end{center} \end{multicols} %@Correction: On a :\\ \begin{center} \begin{tabular}{cccccc} $B \ \in\ [AE]$ & \qquad \qquad & $B \ \in\ [AD]$ & \qquad \qquad & $C \ \notin\ [ED]$ \\ $C \ \notin\ [AB)$ & \qquad \qquad & $E \ \in\ [AD)$ & \qquad \qquad & $E \ \in\ [AB)$ \\ $B \ \notin\ [ED)$ & \qquad \qquad & $B \ \in\ (ED)$ & \qquad \qquad & $B \ \in\ [AB]$ \\ \end{tabular} \end{center}